Dec 1 : 'The type of function you are dealing with is a first order polynomial
like f(x)=ax+b'.

Dec 2 : 'The type of function you are dealing with is a second order polynomial
like f(x)=ax^2+bx)+c'.

Dec 3 : 'The type of function you are dealing with is a third degree polynomial
like f(x)=ax^3+bx^2+cx+d'.

Dec 4 : 'The type of the function you are dealing with is a nth degree
polynomial like f(x)=(a1)x^n+(a2)x^(n-1)+(a3)x^(n-3)+...+(an)'.

Dec 5 : 'The solution of ax+b=0 is x=-b/a. If you want to find the interval
in which the function f(x)=ax+b can be defined, see the following rule:
** Since f(x)=ax+b and a<0, when -oo<x<(-b/a), f(x)>0;otherwise, f(x)<=0 !!!'.

Dec 6 : 'The solution of ax+b=0 is x=-b/a. If you want to find the interval
in which the function f(x)=ax+b can be defined, see the following rule:
** Since f(x)=ax+b and a>0, when -oo<x<(-b/a), f(x)<0;otherwise, f(x)<=0 !!!'.

Dec 7 : 'The equation ax^2+bx+c=0 has not a solution in the field of
Real Numbers. It has its roots in Complex Plane !!!'.

Dec 8 : 'Since D=0, the equation ax^2+bx+c has two equal solutions. These are
x1 = x2 = -b/2a !!! '.

Dec 9 : 'Since D>0 the equation ax^2+bx+c has two distinct solutions as follow
x1={-b-SQRT(D)}/2a and x2={-b+SQRT(D)}/2a !!!'.

Dec 10 : 'Since the equation you have is like ax^3+bx^2+cx+d=0,you can find the
solution of this equation by looking into factors of d. The factors which
satisfy the equation are solutions of our equation !!!'.

Dec 11 : 'Since the equation you have is like ax^3+bx^2+cx=0, you can reduce
the degree of equation by dividing both sides by x. Hence you can use one of
the methods given for second order equations !!!'.

Dec 12 : 'Since the equation you have is like (a1)x^n+(a2)x^(n-1)+...+(an)=0,
you can find the solution of this equation by looking into factors of an. The
factors which satisfy the equation are solutions of our equation. For example,
if a factor of an was 2, you would divide equation by (x-2) to separate it to
its factors. When you continue on like this, you should find all the solutions
of the equation !!! '.

Dec 13 : 'Since the equation you have is (a1)x^n+(a2)x^(n-1)+...+(a(n-1))x=0,
you can reduce the degree of equation by dividing both sides by x with least
degree so that you can use one of the methods given for second or third degree
equations'.

Dec 14 : 'The graph of this first order equation is a line which passes
through the coordinates x=-b/a, y=0'.

Dec 15 : 'The graph of this second order equation is a parabola whose legs
are towards upper half-plane'.

Dec 16 : 'The graph of this second order equation is a parabola whose legs
are towards lower half-plane'.

Dec 17 : 'The graph of this third degree equation is a cubic shape'.

Dec 18 : 'Equations more than third degree cannot be plotted in a three
dimensional space '.


Question 1 : 'What is the biggest degree of x in the equation?'
   Why ''
   Answers  1 'One'
            2 'Two'
            3 'Three'
            4 'more than three'.

Question 2 : 'What is the sign of the coefficient of x with biggest degree?'
   Why ''
   Answers  1 'Positive(+)'
            2 'Negative(-)'.

Question 3 : 'Do you want to learn the type of the function or its solution?'
   Why ''
   Answers  1 'Type'
            2 'Solution'
            3 'Graph'.

Question 4 : 'What is the value of discriminant(f(x)=ax^2+bx+c,D=b^2-4ac)?'
   Why ''
   Answers  1 'Less than zero'
            2 'Equal to zero'
            3 'Greater than zero'.

Question 5 : 'Is there any constant value in the equation? '
   Why 'To be able to find the solution we look into, find the constant '
   Answers  1 'Yes'
            2 'No'.

Rule 1 :
   Why ''
   IF q1a1 and (q2a1 or q2a2) and q3a1 THEN d1.

Rule 2 :
   Why ''
   IF q1a1 and q2a1 and q3a2 THEN d5 .

Rule 3 :
   Why ''
   IF q1a1 and q2a2 and q3a2 THEN d6 .

Rule 4 :
   Why ''
   IF q1a1 and (q2a1 or q2a2) and q3a3 THEN d14 .

Rule 5 :
   Why ''
   IF q1a2 and (q2a1 or q2a2) and q3a1 THEN d2 .

Rule 6 :
   Why ''
   IF q1a2 and q3a2 and q4a1 THEN d7 .

Rule 7 :
   Why ''
   IF q1a2 and q3a2 and q4a2 THEN d8 .

Rule 8 :
   Why ''
   IF q1a2 and q3a2 and q4a3 THEN d9 .

Rule 9 :
   Why ''
   IF q1a2 and q2a1 and q3a3 THEN d15 .

Rule 10 :
   Why ''
   IF q1a2 and q2a2 and q3a3 THEN d16 .

Rule 11 :
   Why ''
   IF q1a3 and q3a1 THEN d3 .

Rule 12 :
   Why ''
   IF q1a3 and q3a2 and q5a1 THEN d10 .

Rule 13 :
   Why ''
   IF q1a3 and q3a2 and q5a2 THEN d11 .

Rule 14 :
   Why ''
   IF q1a3 and q3a3 THEN d17 .

Rule 15 :
   Why ''
   IF q1a4 and q3a1 THEN d4 .

Rule 16 :
   Why ''
   IF q1a4 and q3a2 and q5a1 then d12.

Rule 17 :
   Why ''
   IF q1a4 and q5a2 and q3a2 THEN d13 .

Rule 18 :
   Why ''
   IF q1a4 and (q5a1 or q5a2) and q3a3 THEN d18 .